(2x-1)(2x+1)=4(x^2-3)

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Solution for (2x-1)(2x+1)=4(x^2-3) equation: 


Simplifying
(2x + -1)(2x + 1) = 4(x2 + -3)

Reorder the terms:
(-1 + 2x)(2x + 1) = 4(x2 + -3)

Reorder the terms:
(-1 + 2x)(1 + 2x) = 4(x2 + -3)

Multiply (-1 + 2x) * (1 + 2x)
(-1(1 + 2x) + 2x * (1 + 2x)) = 4(x2 + -3)
((1 * -1 + 2x * -1) + 2x * (1 + 2x)) = 4(x2 + -3)
((-1 + -2x) + 2x * (1 + 2x)) = 4(x2 + -3)
(-1 + -2x + (1 * 2x + 2x * 2x)) = 4(x2 + -3)
(-1 + -2x + (2x + 4x2)) = 4(x2 + -3)

Combine like terms: -2x + 2x = 0
(-1 + 0 + 4x2) = 4(x2 + -3)
(-1 + 4x2) = 4(x2 + -3)

Reorder the terms:
-1 + 4x2 = 4(-3 + x2)
-1 + 4x2 = (-3 * 4 + x2 * 4)
-1 + 4x2 = (-12 + 4x2)

Add '-4x2' to each side of the equation.
-1 + 4x2 + -4x2 = -12 + 4x2 + -4x2

Combine like terms: 4x2 + -4x2 = 0
-1 + 0 = -12 + 4x2 + -4x2
-1 = -12 + 4x2 + -4x2

Combine like terms: 4x2 + -4x2 = 0
-1 = -12 + 0
-1 = -12

Solving
-1 = -12

Couldn't find a variable to solve for.

This equation is invalid, the left and right sides are not equal, therefore there is no solution.

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